Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
I will start with the truck size in meter 10*2.5*4 that’s mean 100 cubic meter of dirt .
Now lets say this mountain is a big pail of dirt and it is weight about 100 kilo for 1 cubic meter .
With this weight a truck go 32 kilometers for an hour in average, and with out the dirt is going 80 kph.
So it will take a truck 0.5 hour to go and 12 min to come back (the average distance is 16 kilometer(10 mill)-more at the beginning and less at the end).
The dirt is very easy to unload 2 min.
And to upload- the truck have to come to the bottom of the mountain and loud dirt which take some time around the 16 min so all together in min= 2 30 16 12=60 to upload and unload and return for one more round.
Because it is very impotent to the city (: there is 500 trucks that work 8 hours a day 5 days a week.
So for each day we can transfer 500 truck*100 cubic meter each time* 8 times= 400,000 cubic meter for day.
The mountain is an cone the height- 900 meters and also the width is 900 m.
So radius=450 450^2*900*pie/3 is around 190m.
But because its a mountain and not a cone i assume its a Little bigger so 200 million cubic meters.
200,000,000/400,000= 500 days or 100 weeks or 25 month or 2 years and one month to relocate it.
If its with one truck only we need to multiply the days by 500.
good luck to them
12 years
1827916694 minutes
let s assume that the mountain is 150 000 m3 in volume
that the bucket of the equipment is around 1.5 m3
that the speed of the equipment is 40 miles/hour
that per day work schedule is based on 10 hours
so in one hour equipment can do two trip or (1.5m3X2)= 3m3
per day it can do 3m3x10=30m3
total nbr of working days will be 150 000/30=5000days or 5000/365=X nbr of years
Approximately 1,000,000 hours
I think the total time =( the volume of an average size mountain/the volume of an average size truck)*the unit time for truck’s transporting once;
I guess the size of an average mountain is: 100 m*100 m, and the pick is 30 m high:
the volume of an average mountain=(100 m*100 m*30 m)/3=100,000 m3;
and I think the volume of an average size truck=3 m*8 m*2 m=48 m3≈50 m3;
the unit time for transporting once=loading time transporting time unloading time return time;
and the transporting time=distinction/the speed=10 miles/40 miles per hour=0.25 hour=15 min;
as well, the return time=transporting time=15 mins;
the loading time, I guess, is about 5 mins with the help of excavators, and the unloading time is only 1 min.
so, the unit time=5 mins 15 mins 1 min 15 mins=36 mins;
The total time=( the volume of an average size mountain/the volume of an average size truck)*the unit time for truck’s transporting once=(100,000 m3/50 m3)*36 mins=72000 mins=1200 hours.
It would take 40 months to move it.
A mountain with a diameter of a half mile and a height of a quarter mile is about 480,000 cubic meters (using 1600 meters as a mile, 400m x pi x 400 squared /3). A truck with a capacity of 10 cubic meters would take 600 days to move if a round trip is about an hour (15 minutes one way, plus 10 minutes for loading and 10 minutes for unloading). Assuming the mountain was destroyed by another crew (not the truck driver), the mountain could be demolished with dynamite in probably a similar timeframe (one dynamite blast could be around 10 cubic meters). So with one day of demolition lead time, it would take around 601 working days with one truck. Working 5 days a week this would be about three years and four months.
Considering a truck with a size rate of 1:500 in relation to the mountain, it would take 1000 trips to move the mountain, 500 with a load and 500 empty. With a 40mi/h speed when the truck is empty and 20mi/h when the truck is full. The total amount of miles traveled is 2000, so the truck would take 25 hours to move while empty and 50 hours while full, giving us a total of 75 hours. We also consider that the truck can travel 5mi/L of gas, with a 50L tank, and taking approximately 20 minutes to travel to the gas station and back with the loading of the gas, it would take 2.6 hours in total. Adding this to the travel time, it would take approximately 77.6 hours to move the mountain 10 miles away on a single truck.
3 Billion hours
75’000’000 Days