Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
An average size mountain would usually be about 4000m high and approximately 2000m long. The surface area of the mountain would be 2000m x 4000m = 8000000m2 though I’m aware that the shape of the mountain is not regular but assuming that those values are estimates.
A dump truck dimension would normally be about 8 m long and about 3 m high hence SA= 8m x 3m = 24 m2.
I would assume we use an excavator to load the truck. The excavator consist of a bucket and its surface area would be about 1 m x 1m = 1 m2.
Considering the excavator is heavy machinery and slow to operate – let’s assume it will take approximately 5 min for the excavator to be positioned in the right place, rotate left to right, dig into the dirt, lifting the dirt and offloading it onto the dump truck. The dump truck can store a max of 24m2 (1m2 x 24m2) thus 5min x 24 m2 = 120 minutes ( 120/60 min = 2 hours) . It takes about 2 hours to load the dump truck. It is 10 miles to the new location. Considering that the roads won’t be in the best possible shape next to mountains , I would assume the truck won’t be going at a greater speed than 20m/h. Therefore it will take half an hour to do the 10 miles to get to the new location. Also, another 15 minutes for the truck to be positioned in the right place and offload the dirt in the new designated place. Another 30 minutes to get back to the mountain. So in total it will take approximately 2h ( to load the truck) 1 h ( journey back and forth) 15 min (to offload the truck) = 3.25 for one truck. Let’s assume that it will be a 10 h shift a day (including the break) there will be approximately 3 trucks per day. 3 trucks each containing 24m2 of dirt therefore 3x24m2 = 72m2 per day. Let’s assume the workers work only Mon-Fri therefore 5x 72m2 = 360m2 in 5 days. If we find out how long it will take for 8million m2 of dirt to be relocated (8million m2 x 5)/360m2 = 111111.11 days – which means it will be better for the mountain not to be relocated.
I gave it a try, though the values seem ridiculously big.
Assumptions: Truck – 10 Tonnes 2000 cubic feet in one trip
Mountain – 200 metre square wide 500 m high volume -900000cubic feet
Time for loading/unloading – 1 hour
Final Answer: 45 Days 10 hours
50 hours
just assuming that moutain average weight 50000 tonn, and truck load is 50 tons/h per mile we would need 10 tracks for 1000 hours
1. assume the mountain is made of just solid dirt, ignore floor and fauna, empty space, bodies of water
2. assume it is a perfect cone
3. Total dirt on a mountain. i’ve been skiing on really high peaks about 10,000ft high , so let’s say the average is around half of that, 4000 ft high. Estimate a cone of 4000 ft high with bottom radius 4000 ft. this is a very nice and geometric cone. Then total volume of cone is 1/3 * h * r^2 = 1/3 * 4000^3 = 1/3 * 64 * 10^9 = roughly 22 * 10^9 cubic ft of dirt.
Assume the “average truck” is a pickup truck.
Volume of truck bed = 2 ft high (i rode in the back of a truck once), 6 ft long (i’m 5 ft tall, i could lay down in it and then some more), 4 ft wide (can seat 2 people across, about 2ft/person)= 48 cubic ft.
It will take 22/48 * 10^9 round trips, or 0.5 * 10^9 =
5E10 round trips.
r = d/t -> t = d/r
time for one round trip = 10m/S 10m/E
S = speed of average fully loaded pickup truck = 20 mph – the driver is being safe.
E = speed of avg empty pickup truck (on the way back) = REALLY FAST, 100 mph
Assumptions: no stops for gas at all. the drivers spend no time switching out. Loading and unloading don’t take any time – conveyor belts make that time neglible.
= 10/100 10/20 = 0.1h 0.5 h = 0.6 * 60 min = 36 min for one round trip
36 min * 5E10 trips = 180 E10 min = 3 E10 hours
Time to deliver a mountain in 10 miles with an average truck=
volume of the moutain / (volume carried by a truck * delivery times/day)
a. volume of a mountain=1000 m3
b. volume carried 4 m3/time
c. truck works 8 hours /day, each delivery counts 2 hours, thus 4 delivery per day
d. 1000/(4*4)=60 days
9 days
60 Million Hours
To start, i will assume that an average sized mountain has a radius of 30 meters and is a semi-sphere. Knowing that, it’s easy to calculate the volume of the mountain, which is 4*30*30*pi/6. That volume is approximately 2800 m3. I will also assume that an average sized truck has a bucket with a capacity of 20m3. Therefore, it would take 140 trips to move all the mountain content. In my hypothetical situation, we have a bulldozer with a scoop that can handle 0.5 m3. Assuming that the bulldozer takes 1 minute to fill the scoop and drop the content into the truck bucket, it would take 40 minutes to fill the truck bucket. To travel 10 miles, the truck would take around 25 minutes, and to drop the content of the bucket, around 5 minutes. So, the total time of a trip is 40 25 5 which is 70 minutes. If the service is done 8 hours a day, we would have around 7 trips a day, considering possible delays. Therefore, we would need 20 days to move all the mountain’s content, which is around one month, considering that it wouldn’t work on weekends
800,000 days
Assuming 3 persons, 8 hours shift, working night and day