Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
It will take about 400 years to move the entire mountain.
Assume the size of an average-size truck is 3m(width)*5m(lenth)*3m(height)≈50(m^3). Assume an average mountain has an radiation of about 10km, a height of 2km. So the volume of the mountain is 1/3*2km*(π*10km^2)≈2*10^11(m^3). So it takes (2*10^11)/50 times to move the mountain, which equals to 4*10^9 times. Think each time takes 1 hours (including the upload and download of the truck, the travel time for 10 miles). It takes about 4*10^9 hours in total.
I think 1st that since the average size of mountain is 10 mile which is 52800 feet and each feet contain 25 ton material so the total material = 1320000 ton and the average size of truck is 50 ton it can replace it in = 16400 round
Turn the question to: how many average sized trucks would fit into an average sized mountain
1) Average sized truck = (2x10x5) = 100 cubic meters
2) Average sized mountain = 3000 x 3000 x 3000 / 3 = 9 x 10^9 cubic meters
So we need 9 x 10^9 / 100 = 9 x 10^7 trucks
Say truck has to run slowly, so 10 miles takes 1/4 hours (40 miles / hour), so each trip (there and back) = 1/2 hours
Thus: how long = hypothetical number of trucks x trip length = 9 x 10^7 x 1/2 = 45 x 10^6 hours = 45 million hrs
Hi Victor,
Thank you very much for sharing your wisdom! I have just been informed that I passed my first round McKinsey interviews. Currently I have been asked to schedule my video interviews next week and I was wondering
1. if that enough time? (1 session in 5 days and another 2 in 9 days with partners)
2. How should I prepare?
3. Do you recommend delaying it for another week for in person interview
The main feedback from the first round was weak structure (issue tree) and rushing in formula generation.
I have just gotten a LOMS and hope to improve with it.
Thanks again for all the help so far!
(Ps: I will hopefully join the Jakarta’s office. Do let me know if you are in town, I would like to buy you lunch)
Regards,
Donald Aditya
Assumptions:
1) the weight that an average size truck can haul: 8*10^-3 cubic kilometer (length 400m, width 200m, height 100m)
2) the volume of an average size mountain (assuming it is shaped like a cone with radius of 2 km and height of 2km): ~24 cubic kilometer
–> the truck needs to ship 3000 times to move a mountain
3) truck speed: 10 miles / o.2 hour
4) Time for two people to dig the mountain, and load and discharde goods: 1.8 hour
5) These two people can load 80 kg per time -> It takes 100 times to fill a truck up
–> It takes 200 hours for two people to fill a truck up
–> The time it takes to relocate a mountain = 200 hours per shipment * 3000 shipments = 600,000 hours
Assuming the working hours per day are 10 hours, 600,000 hours are equal to 60,000 days, or around 160 years.
1) I would start with defining the average size of the mountain.
The form of a mountain is the most similar to a pyramid, let’s say an average one is 500 metres high, and its base is a rectangle of 2000 and 1000 metres.
We need the volume, as it’s a pyramid, the form is the area of the base x height / 3.
(2,000 x 1,000 x 500) / 3 = 333,000,000 cubic metres
2) Now the truck, if we assume the part for the cargo is 1 meter wide, 3 metres long and 2 metres high, then its volume is 2 x 3 x 1 = 6 cubic metres.
3) 333 M / 6 = 55 M times do we have to use this truck to move the whole mountain away.
4) – let’s make our lives easier with assuming the truck could work 24 hours/ day, in shifts, and we have very good machines, so
– loading the truck: 10 mins
– loading out: 0.5 mins
– while loaded, it could go with 50 km/h, so it would take 12 mins to drive the 10 kms
– on the way back, as it’s empty, it could go faster, with 80 km/h, so it would take 7.5 mins.
– adding these up, one round of bringing one heap away and arriving back empty, ready for the next round would take 30 mins ( 10 12 7.5 0.5)
5) In one day we could do 24 h / 0.5 h = 48 turns
We need 55 million rounds, so we could move to mountain in 55,000,000 / 48 = 1,145,000 days.
Time = time of Truck running with part of the mountain time of Truck running empty (it’s a round trip, the truck will returns empty).
Assumption 1: The mountain is made of stone. Every stone is the same, whose weight=10g, volumn=125cm³(5cm*5cm*5cm)
Assumption 2: The size of the mountain. volumn=216Billion cm³(60m*60m*60m). so the mountain will have 2billion stones(216billion cm³/125cm³), weight=# of stones * weight/stone=2billion * 10g= 20,000tons.
Assumption 3: The average truck can take 5tons of cargo running at a speed of 60miles/hour.
so, time for a truck running with mountain = time for running for 10 miles per commute * # of commutes = (10miles/ 60miles/hour) * (20,000tons / 5tons)=666hours.
Assumption 4: the speed a truck running empty = 70mils/hour.
Likewise, time for a truck running empty = 500hours approximately.
Total time =666hours 500hours = 1166hours= proximately 50days.
I know the highest peaks are upto 8800m and lowest are about 100m . So average heights are about 4450m .
Assuming a mountain to be conical in shape with angle of inclination to be 45 , the volume of the mountain can be estimated as (1/3*pie*r^2*h) . where h=r=4450m
The volume of a truck can be estimated as : 1.5m *1.5m*1.5m
No. of trips required are : total Volume/volume of truck
=27.3 billion trips
The average speed of a truck is about 50 miles per hour : time taken in a round trip is 24 minutes
27.3*24 billion minutes=655.2 billion minutes
or 1.246 * 10^6 years
assume the average size of truck can only move 1% of an average size mountain, and the truck with the heavy load moves slower than usual, 20pmh.
load and unload takes 10 min. time on the road is 30min. and 100 times * 40 min = 4000 min