Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
An average size truck does not have the force to overcome the inertial force of the mountain. The answer would be infinity.
– truck can carry 50m^3
– mountain is 5000 m^3
– truck has to move 100 times at a speed of 60 miles per hour
So only transport takes up to 10 minutes ( 2 directions: 20 min) x 100 times that he has to go is up to 33 hours, lets say 32 hours, so 4 full days. But how long does it take to put 50m^3 on the truck and to put it down again once the new location is reached? totally lets assume 4 hours. per 100 times would mean 400 hours. So 400 32 hours. Lets assume 480 if something doesnt go smooth – so total of 60 days.
120
My approach:
What is the exam question:
How long >> days / months / years?
Solution Formula:
how long = time for 1 round trip (c) * # of trips
# of trips = mountain volume (a) / truck volume (b)
Breakdown of components:
(a) “average size” mountain = ?
– assume shape = cone
– hence, total volume = 1/3 * cylinder volume = 1/3 * pi * radius ^ 2 * height
– assume moving rocks / stones / dirt only (vs. trees)
(b) average size truck = ?
– assume capacity fit into shape = rectangular
– total volume = height * length * width
(c) 1 round trip = how long?
– assume 10 km on straight, flat, paved road (other alternatives include hilly / curve / hilly / unpaved roads)
– assume time to move limited to 8 hours per day, 40 hours per week, 4 weeks per month (e.g. in a construction site)
– one-way time = distance / speed
– round trip = one way * 2
Once this framework is setup, all one does is to plug in some made up numbers (try to use easy ones that can be divided wholly) and set up a story (context) to help bring to life the reasoning process (e.g. can be a likely real story like construction in the Tibetan Plateau that requires a mountain to be moved to make way for brand new high speed rail….).
It will take about 3 years.
It needs to work about 20 hours a day and each trip will be about 1 hour means 20 trips a day or 330 *20 trips a year – in all about 20000 trips each of 400 cubic ft of matter.
Assumptions / considerations:
– Supply: Mountain is broken and can be loaded with no bottlenecks (using reclaimers etc)
– Mountain size: is approx. 600 million tons
– Demand/Uptake: Truck has no mechanical issues and refueling is factored in
Avg Truck Size: 30 tons
Avg Truck turnaround: 20m /30mph = 40 mins 6.5 min (ldg avg) 3.5 minutes (dumping, avg) .
Hence truck moves 1 load of 30 tons every 50 mins. factor in Fueling at 10 minutes
Therefore 600 million /30 = 2 million loads total
Based on this, it would take 2 million loads x 50 minute trips = 100 million minutes @ ~1,500 minutes in a day = ~70,000 days /350 days = 2000 years
70days
First, let’s estimate the size of the mountain. We can assume it is a cone with a radius of 1 mile and a height of 1 mile. So the volume of the mountain will be pie*1^2*1*1/3, and if we round pie to 3, we have the volume 2 mile^3. A regular truck can load 2 tonnes of stuff, and that is approximately 1.6*1.6*1.6 m^3. So the truck will need to go back and forth 2*(1.6*1000)^3/1.6^3 = 2*10^9 times. Assume the speed of the truck is 20 miles per hour, to go back and forth once will take 1 hour. So that will be 2*10^9 hours. 5 days is 24*5=120 hours, and a year is around 365/5 = 73 units of 5 days, which is around 120*70 = 8400 hours. 2*10^7/84 –> 0.25^10^7 = 2500000 years.
3k3min
Comparing the mountain to a building with 50 floors ,each one crowded with 100 people.
Assuming a truck moves at 20 miles an hour if loaded with 250 kgs, we get 6o hours.