Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
1/3 (B^2) * H = Area of triangular prism.
If the mountain were 2,000 feet tall, ~1 mile per side wide (5,000 ft), (~16,666,666,666 cubic feet), and a pickup truck’s bed is 5x6x2 (60 cubic feet), then it would take ~277,777,777 trips.
Driving 60 miles per hour, it would take 12 minutes per round trip (with no stops).
277,777,777*12 minutes = 3,333,333,333 minutes / 60 min per hr / 24 hr per day = 2,314,814 days, or 6,341 years.
How many boulders with 1500 kgs can sustain by 18 cubic dumprtuck?
100 years probably for my truck
My truck would need 3000 years.
90days
2*10^11 hours
To find out the answer, we need to estimate the volume of an average mountain and the volume of space available in an average truck and the speed at which the truck can travel back and forth between the two locations. Plus we also need to know the loading and unloading time of the truck.
Time required would be no of time the truck would have to load, go the new destination, unload and comeback multiplied by time taken for each cycle.
Time taken = no. of cycles * time per cycle
now time per cycle = Load time unload time time taken in going to the destination time taken in returning back
these day machines are available which can quickly load/unload a truck. I thinks it will take maybe 10 seconds for each.
Also distance is 10 miles. truck would be slow when travelling with full load as compared to when empty. An empty truck can move at say 50 miles an hour whereas a loaded truck may move at say 30 miles an hour.
therefore time taken in round trip would be (10/50 10/30) hrs.
so out cycle time is (10 sec (10/50 10/30) hrs)
now no. of cycles would be volume of mountain/volume of space in truck.
mount Everest is 8 km high. so I would take an average mountain to be half of that say 4 km. Also a mountain can be taken as a cone having apex angle of 45 degrees.
therefore the volume of mountain would be (using the formula to calculate volume of a cone) = (1/3)*pi*r*r*h = (1/3)*3.14*2*2*4 = 16 km cube (approx)
now volume of an average truck. I can assume the average truck to be a cube with a side of about say 20 ft or 6 meters.
therefore volume of truck is 6*6*6 metre cube = 216 metre cube
therefore no of cycle required is (16*1000000)/216 = 80000 approx.
so time required = (10 sec (10/50 10/30) hrs) * 80000
((32*60 10)/3600)*80000 hrs
(800/36)*( 1930) = 40000 hrs (approx)
2,017 days, 8 hours, 20 mins
10 MILES DIVIDED BY THE SPPED OF THE TRUCK
I would assume:
average mountain height: 900m
average mountain base diameter: 8km
Noting that a mountain resembles a cone I would apply the formula: V= 3,14 x r x h/3 and obtain a total volume of 3768 m3.
I would then estimate the truck capacity. Assuming that an average truck has a 7m long, 3m tall and 3m wide loading space, the total capacity of the truck is 63 m3.
It is now time to divide the volume of the mountain by the truck capacity to estimate how many 10 miles long trips will take the truck to move the mountain; the result is 3768/63= 60 ( rounded number, the exact result is 59.8).
Assuming an aveage speed of 20mph it takes the truck 1h for each round trip; this means 60 hrs driving.
To this number we have to add loading/ unloading time. I assumed a loading time of 1h and a 30mins unloading time (1,5hrs per truck load in total). Multiplying this number by 60 truckloads we obtain 90hrs in total.
My final estimation is therefore 60 90 = 150
Francesco
OOps, silly mistake. The mountain volume is 3678000 m3; it takes the truck 60000 trips = 60000 hrs 90000 hrs of loading/unloading operations. Total time required: 150000 hrs = 411 years.