Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
We need to estimate the average size of a mountain and the average capacity of a truck. The truck size is relatively easy to guess. Let’s say 5m*3m*2m=30m^3. The height of a mountain ranges from a few hundred meters to 8848 meters. Let’s simply assume that it’s 1000 meters high and it’s a perfect cone shape with the diameter of the base as 1000 meters. The total volume of the mountain is then 1/3*PI*(1000 m)^3 ~ 1*10^9 m^3. Assume the speed limit for the truck is 40 mile/h, then a round trip takes 20/40 h=0.5 h. Neglect the time for loading/unloading, the total time needed would be 1*10^9/30*0.5 ~ 2*10^7 h, or ~ 2000 years.
volume of mountain = 4/3 pi (10000)^3
volume of truck = 3*2*2
no. of trucks required = (10^12)/3
digging speed = 10 trucks per hour
digging time = (10^11)/3
filling time = (10^10)*2/3
truck speed = 60mph
total transportation time = 10*2/3*(10^10)
therefore total time = 10.67*(10^10)
It possibly takes 3240 estimated hours to move an average sized mountain 10 miles using an average truck.
An average size mountain would be 3.5 km in height(I am estimating this on the basis that the highest mountain Everest is 8 km high). In terms of diameter, I would say approximately 12km, so radius is 6 km. Assuming a cone shaped mountain, the volume would be 1/3×22/7x(6000m)^3x3500m=appox 800×10^12m^3. Assuming density of 10kg/meter cube, since water has a density of 1kg/meter cube, the weight would be 800×10^13 kg. Assuming an average truck has a capacity of 1 tonne, i.e. 1000 kg, the truck would have to make 800×10^10 trips. If it has be relocated across 100 km, and travels at a speed of 20km/hour while going and 50km/hour while coming back empty, the journey would take approx 7 hours, it would take 5600×10^10 hours. which is approx 80 billion months, assuming approx 700 hours in a month and 21 billion years, considering there are 12 months a year.
Total time = Time traveling with garbage time traveling without garbage.
Time traveling with garbage = Number of time traveling x time per travel = Mountain volume/ truck volume x (travel time dumping time).
Mountain volume = 1/3 x pi x r^2 * h
Average mountain –> h = 1000m, r = 50m (assumption)
pi is rounded down to 3, so:
Mountain volume = 50^2 x 1000 = 2,500,000 m3
Average truck has a 2 x 3 x 4 load, so the volume is 24 m3 which is rounded up to 25
The average travel velocity is 20 mile/hour, so 10 miles mean 0.5 hour.
Dumping time is 6 minute, which mean 0.1 hour
Time traveling with garbage = 2,500,000/25 x (0.5 0.1)
Similarly, time traveling without garbage = 2,500,000/25 x 0.5.
So total time is 2,500,000/25 x 1.1 = 100, 000 x 1.1 = 100, 000 10,000 = 110,000 (hours) = approximately 4400 days
Average Mountain – 1000 tonnes of earth and stone
Capacity of a Truck is – 20 Tonnes carrying capacity
Distance to move – 5 miles
Truck Speed when fully loaded 20 mph
Time to Load/Unload to full capacity 3 hours
Total Trips in a Day 2 mountain moved in a day 40 Tonnes
Time required – 1000/40= 25 days
Average Mountain – 1000 tonnes of earth and stone
Capacity of a Truck is – 20 Tonnes carrying capacity
Distance to move – 5 miles
Truck Speed when fully loaded 20 mph
Time to Load/Unload to full capacity 3 hours
Total Trips in a Day 2 mountain moved in a day 40 Tonnes
Time required – 1000/40= 25 days
average mountain: 1 km height with 1 km radius bottom and it is cone like. So the volume: pi*r*r*h*1/3 = 3.14 * 1000 * 1000 * 1000 *0.33 = 1.04 * 10 (9) m(3)
Mountain made of rocks: rocks consist major with silicon dioxide (major component of sands, sands are small pieces of rocks). The density of silicon dioxide is around 2.5 t/m(3)
So the total mess is around 2.5 * 1.04 * 10 (9) = 2.6 * 10 (9) t
The decomposition of the mountain do not need a long time ( several years maybe) as we have so powerful dynamites. Thus, the time needed in this case is omitted.
A normal truck in China ( I am a Chinese) can hold 4t of cargo.
So it will take the truck around 6.5 * 10 (8) times go-and-back journeys. Which means the truck need to load and unload for this much times and the total miles covered during the journey is around 1.3 * 10 (10) miles.
To load 4 t of rocks onto a truck, if you have a right lifting machine, it will take around 15 min. For unloading, you just need to pour out all the rocks, so will take only 5 min at most.
The truck carrying rocks cannot drive so fast (for safety), I set its speed at 40 miles/h (which is a quite high speed for a truck with cargo in China). Then the return journal will take 30 min.
Therefore, each journal will take around 50 min.
Then the total time we need is
6.5 * 10 (8) * 5/6 = 5.4 * 10 (8) hrs
= 2.25 * 10 (7) days = 6.2 * 10 (4) years
So I will probably need 62,000 years.
Lastly, one truck can never do this job as it cannot last so long.
1.5 million years
My truck would take 5k years