Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
assume pyramid shape
ht 2000m, base 3000m X 3000m
volume of pyramid = 2000 x 3000 x 3000/3 = 6 x 10 power 9 m3
TRUCK
truck bed size = 4m x 2m x 0.5m = 4m3
speed = 60mph
time to go with load= 10mts
time to come back empty = 10mts
time to load = 40mts
So, 1 trip per hour
operating hrs = 12, so 12 trips/day
NUMBER of trips = 1.5 x 10power9
NUMBER of days required = 1.25 * 10power8
truck operation = 365 days per year
number of years = 1.25 x 10power8/365
estimating ( rough calculation) = 3.33 x 10power5 years
Assuming that the average height of a mountain is 6,000 ft, and the base has a diameter of the same 6,000 ft, the square area of the base is appx 28M sq ft and the volume is appx 85B cu ft, or appx 3B cu. yds of dirt/rocks.
Each truck can hold 30 cu. yds of material. Therefore, 100M truckloads of material must be moved. If it takes 1 hour to load the truck, drive it 10 miles, unload the truck and return, then it would take 100M hours to move the mountain. At 24hrs/day and 365 days/yr, this works out to appx 11,000 years.
Assuming a mountain that is 10000 feet tall and 6000 feet in diameter, and assuming a standard sized truck that can move a volume of dirt that is 4 feet by 4 feet by 8 feet, I have estimated that it would take 366, 555,762 hours to move this mountain 10 miles.
8 * 10^8 days.
To gauge the size of a mountain, I compare it when looking at it as a background to my house. It needs to be much bigger than my house (not a hill). So suppose the ground floor of my house is 3,000 square feet.
It takes roughly 100 of my houses to span the diameter of the mountain (from one side to the other). For sake of the calculation, assume the mountain is relatively spherical after adjustments are made for its irregularities. Therefore it is 300,000 ft diameter.
Calculating then the volume of the mountain, using 0.5*(pi)*(radius)^2, where radius in this case = 150,000. The volume of the mountain is 11,250,000,000 ft^3.
Then consider the average size moving truck. Call it 20 ft x 10 ft x 10 ft = 2,000 ft^3.
Dividing these two values, it takes approximately 5,625,000 trucks to move the mountain. Carrying a full truck, we cannot exceed 20 miles per hour for fear of tipping over, starting and stopping, each round trip takes one hour, plus 30 minutes per loading period. (one load one unload)
That is 5,625,000 hours of loading/unloading and 5,625,000 hours of driving = 11,250,000 hours.
I would start from calculating this mountain volume in m3.
The formula is V=1/3*S*H. Lets assume H=1000m high and the base looks like a big not ideal circle. Circle square equals A=Pr^2 with r=2500m and P=3.14
So our formula equals V=1/3*(3.14*2500*2500)*1000. Roughly estimate will be 6.3B cbm.
Then lets estimate volume of average truck. Assume it has standard box-like space for load with 2m height, 3m lenght, and 2m width which gives us H*L*W = 12cbm as volume of average truck.
Lets calculate number of trucks needed to move the mountain. For that we divide 6.3B by 12 which gives us roughly 525M of trucks.
Distance of 10 miles equals 18 km=18000 m. Avg speed for truck is 50 km/h leads us to 22 min one way per truck.
There is also time for loading the truck. Assume it takes another 10 mins for loading it and 8 mins to unloading, 18 totals.
As given we have 1 truck, means it needs to go one way full, and empty back so we need multiply 525M by 2 = 1B trips for 1 truck.
So in the end we calculate 1B trips*(22 10 8)=1B trips*0.67 hour = 670M hours for 1 truck => => roughly 70.000 years
50,000 years
Let’s say a average a average mountain is 2500m high and 5000m in diameter. With h*r*Pi/3 this makes roughly 5.25 million tons, when one ton equals one m³.
Our average truck can load 20 tons, this means the driver needs 2.5 millions loads. With 20miles to go for each trip and an average speed of at least 50mls/h, this would make roughly 25mins per trip.
To sum this up, it would take 5.25 million minutes, 90000 hours, 3600 days or roughly 10 years (including some holidays).
70 minutes total time trip ( 5 to charge 30 min to go , 5 decharge and 30 min come back )
1 truc is 0,01% Total quatity of dust in a mountain
therefore 70 min * 10 000
Which give us : 1 year 121 days
Assuming average size of mountain (in Pyramid shape)
= (length x breath x height) /3 = (1000 x 1000 x 1000)m / 3
= 333,333,333 cubic meter
= 333,333,333 tonne (assuming 1 cubic meter = 1 tonne)
Assuming average truck load is 200 tonne
=> it will require (333,333,333 ton/200 ton) = 1,666,667 trucks loads to shift the mountain.
Assuming it takes 10mins to fill up the truck;
Assuming average truck speed is 10 mins to travel 10 miles
=> will take about 20 mins for the round trip
Therefore, it will take 30 mins to fill the 200 tonne truck, drive to dump 10 miles away and return for another load.
HENCE, it will require 1,666,667 trucks loads x 3omins or 0.5hr
=833,334 hr = 34,722 days = 95 years if using 1 truck; 9.5 yrs if using 10 trucks; and about 1 yr (11.5 mths) if using 100 trucks.