Case Interview Example – Estimation Question and Answer
I was asked the following management consulting estimation question by a McKinsey interviewer many years ago:
“Estimate how long it would take to move or relocate an average size mountain 10 miles using an average size truck”
Below you will see my answer to this estimation question and the process and rational I use to answer this specific question can be used as a template to practice answering other estimation questions as you prepare for case interviews.
The first thing to realize in an estimation question is that an acceptable answer MUST mention a specific number.
This question was how much time it takes to move an average mountain 1 mile (or something along those lines).
If the answer does not include a specific unit of time like X hours, Y days, Z years, then the answer is not acceptable.
By the way, I use the word “acceptable answer” instead of “correct answer” very deliberately. The interviewer’s evaluation in this type of question is in assessing the approach you took, not necessarily the specific answer you gave.
The next thing to the answer must include is that explicit assumptions must be made.
It is not possible to answer this question without making some assumptions. They key is to EXPLAIN to the interview that you are going to make some assumptions. Once you do and once you make a specific assumption, explain your rationale behind that assumption.
For example, when I was given this question. I knew that I needed to estimate the cubic volume of the mountain. And since the mountain loosely resembles a cone, I knew there was a geometric formula to calculate the volume of a cone–except I did not recall the specific formula off the top off my head.
So my interviewer suggested that I estimate the formula of a cone, which in turn I would use to estimate the volume of an average size mountain, which would then be part of a calculation to estimate the average time it would take to re-locate it.
Notice the estimate that is nested within the estimate here. This is very common. Most important thing is to not get mixed up and confused by your own work.
I find it is useful to just write out the formula that will produce the estimate FIRST, THEN go about making reasonable assumptions.
For the move the mountain case, the formula I wrote up on the white board during my interview was:
volume of mountain / volume of a truck * time per truck trip = total time to move a mountain
I would literally write that on the board. That is the amount of time it would take 1 truck to move an average size mountain 10 miles (the 1 truck is an assumption as well)
Then I went about estimating each of those 3 factors.
Assume the average size mountain is 1 mile tall, 1 mile wide, and the shape of a cone. That’s approximately 5,000 ft in height and base.
I forge the formula to calculate the volume of a cone, but if I eye ball it, it is probably a little more volume than half of a cube of similar size height and base.
The volume of a cube that’s 5,000 ft tall, 5,000 ft wide, and 5,000 ft deep is 125,000,000,000 cubic ft.
Since I’m trying to estimate a CONE, and not a CUBE, I’d then take 125,000,000,000 x 50% (my approximate guess as to how much smaller a cone is vs a cube of approximately the same height, and width and length at the base.
With some slight rounding, that gets us 60,000,000,000.
Then underneath my original formula, I would write the following:
60,000,000,000 cubic ft / volume of a truck * time per truck trip = total time to move mountain
Next, I would move on to estimate the volume of a truck.
The carrying capacity of a cargo truck is the width x length x heightof the cargo container.
I said, well I know those big trucks are a little wider than my car, but not by much since they still must be able to fit into a lane on the freeway. My car sits 3 people across, assuming 2 ft in shoulder width per person, that’s 6 ft of interior space. Let’s add on a little more and assume those big trucks are around 8 ft in width.
I know they are about double the length of most passenger sedans. And lets see if I were to lie down in the driver’s seat to take a nap, I cover most of the interior cabin space. And the hood and trunk of the car combined are about the same length as the interior cabin. I’m a little under 6ft tall, so that makes my car around 12 ft long. If I double that, I get the length of one of those trucks to be 24 ft long. I subtract out say 4 ft for the driver compartment, and that leaves me about 20 ft in length for the cargo area.
Last time I looked, I saw a worker standing in the back of one of the cargo areas, and the cargo area was taller than the person. I figure the cargo container is about 8 ft tall. And since most freeway bridges have signs that say “height 13 ft” and I know those trucks can go under those bridges, assuming an 8ft cargo section and a 4ft for the tires and chassis under the cargo area, that gives me 12 ft…which does seem to triangulate with the height of those underpasses. So I’ll say the cargo section is approximately 8 ft tall.
The volume of the cargo area of an earth moving truck is:
8 ft wide x 20 ft long x 8 ft tall = 1,280 cubic feet
For sake of simplicity, I’m going to round that down to 1,250 cubic feet and plug this number back into my original formula which now reads as follows:
60,000,000,000 cubic foot mountain / 1,250 cubic foot truck capacity * time for truck trip = total time to move a mountain
The only factor missing in our estimate is figuring out the round-trip time for a trip to move 10 miles, drop its load, and return the 10 miles. Let’s figure out the travel time first. Assume the truck travels on the freeway at 60 miles per hour.
For it to travel 10 miles, it does so in 1/6 and hour or 10 minutes. The drive time is 10 minutes to the new location, and 10 minutes returning to the old mountain for a total of 20 minutes. Assume that the off-loading process has been designed to be pretty quick. The load is just “dropped” and then repositioned while the truck is on its return trip (as opposed to being scooped out of the truck, one scoop at time which seems more time consuming).
That means each round trip takes 30 minutes or 0.5 hours.
Let’s go back to our formula again and update it.
60,000,000,000 cubic ft mountain / 1,250 cubic foot track capacity * 0.5 hours per truck trip = total time to move a mountain
Let me do the math now. For the first 2 components of the formula, that works out to about 50,000,000 (50 million truck loads).
50 million truck loads x 0.5 hours, thats 25 million hours to move a mountain.
If we assume a typical day has 25 hours (to make our math a little simpler), that’s 1 million days to move the mountain using only 1 truck. That works out to a bit under 3,000 years
That is the logic I just presented is a pretty good one that would most likely pass most estimation question interviews.
You will notice that for every little component I explain WHY I felt that was a reasonable assumption.
There is a big difference between making a wild assumption vs. a reasonable one. Your goal is to make as reasonable assumption as you can come up with. When you make such an assumption, it is very important you explain WHY you made the assumption you did.
The math is not that complicated (it’s math we all learned before high school) BUT communicating what you are doing is just as important.
It is also important that you do not make a math mistake. I wrote out this example quickly and hopefully I did not make a math mistake.
If I did make a math mistake, I would full expect to get rejected even if I got the logic and assumptions largely right.
That’s just the way it works. Practice your mental math. You DO use it a lot not just in interviews but with clients as well.
504 thoughts on “Estimation Question”
Asumme that the truck has the capacity of carrying 10m^2 of earth, and an average mountain has a volume 600 times more than the truck so say 6000m^2. Thus, in order to move the mountain, the truck will need to transport the earth 600 times. Since there is only one truck and its average speed is 30 miles/hr, 10 miles of travelling will take 20 minutes. Also because there is only one truck, it needs to go back and fourth. 600 * 20 = 12,000 minutes, but because the truck has to travel back, we multiply the result by 2, this will be 2,400 minutes in total. 24,000/60 = 400 hours = 16 days
let’s say the height of an average mountain is 10,000 feet, and to make it simple, its bottom is a circle which occupies 30,000 square feet, the volume of a cone equals 1/3*S*h=1/3*10,000*30,000=100,000,000=100 million cubic feet
an average truck can carry 500 cubic feet per time. It takes 10 minutes to load and 10 minutes to unload each round. It takes roughly 10 minutes for the truck to travel 10 miles one way. So to finish a full round: load travel unload travel back = 10 10 10 10=40 minutes
100 million/500 = 200,000 rounds
200,000*40 minutes = 8,000,000
8,000,000/(60*24) = 8 million/1,440 = 5,500 days
so lets think,
define average mountain to be 4.5 km high
volume of piramid shaped mountain is 80 percent of a cube say 4.5 km squared is 16.2 km3
weight of mountain is at 2.5 ton/m3 is approx 40 billion tons
approx truck load is 40 tons
so you need one billion truck loads
say one truck can deliver 10 loads a day at 10 miles distance
if you use 100 trucks, they can together deliver 1000 loads a day , you ll need one million days
thats 2700 years.
If we take the mass of an average mountain to be about 2 million tons. And assume that the average truck can carry about 20 tons of material, it would take about a 100,000 trips. If each trip 10 mile trip @ 60 mph took 10 minutes, all trips together would take ~17000 hours or ~708 days.
Assuming mountain to be in a shape of an quilateral pyramid of each edge of 40m.so we need to shift around 9000m^3 volume.Assuming each truck would be able to shift 5 meter cube at a time and assuming truck travelling with a speed such that it takes half an hour to go to and fro.Hence it would take 900 hours.37 days 12 hours
Assumptions:-
1.Let’s say an averagse size of a truck is 10*12 = 120 m2
2.Let say the average size of the mountain is = 7200m2
3.The truck travels 8 hrs a day
4. The speed of the truck is 36 km/h as it is on mountain range
5. 1 mil = 1000m
The distance travelled = 10 miles
The number of times the truck would have to take a part of the mountain = 7200/120 = 60
The speed of the truck is 10 m/s
Distance = Speed * time
10*1000 = 10*t
t= 1000h
8hrs – 1 day
1000hrs – 125 days
Now the whole mounatin will be moved in 60*125 = 7500 days.
600 million hours
93 000 years
Mountain > Proxy for the overall truck load to be carried over ten miles > Pyramid on a quadratic ground with height h = 2,000 m and and side lengt l 0.25 x 2,000m = 250 m > 500,000 m^3 truck load
Truck > Volume it can carry > 3.5 m x 2 m x 1.5 m = 10.5 m^3
Numbers to Mountain and Truck result in 48,000 truck loadings that are necessary for the Mountain to be moved
Assumptions on speed of the truck over the 10 miles (fully loaded = 45 miles/hr and empty = 50 miles/hr) loading times on the mountain and the spot 10 miles away (1/2 hr and 1/4 hr respectively) result in time needed per one full transport step > 1.2 hrs
Result: 48,000 loadings x 1.2 hrs = 57,600 hrs
– Calulate the volume of the mountain : to simplify, let’s say the mountain has a pyramid shape with 100meters each side and a height of 50meters. Volume = 100 x 100 x 50 = 500 000 m3
– Estimate the volume of the truck : 10m x 2m x 2m = 40m 3, let’s say 50m3
=> Number of going back and forth = 50000
– Estimate the time for loading and unloading the truck and the transport time.
=> Volume of bucket of the mechanical digger = 1m3
=> Time of loading = #bucket x filling time and buckett movement = 50 x 1min = 50 min to fill the truck
=> Loading time = no need for bucket so 5 min to empty the truck.
=> Transport time = truck’s speed is approximately 50km/h at full and 60km/h for an empty truck (mountains roads…) so for 10km it will be 12min for the way to go and 10min to come back.
-> 1 cycle time = loading time Transport time to go unloading time transport time to come back.
-> 1 cycle time = 50 12 5 10 = 77 about 80 min.
Total time = #cycles x cycle time = 50 x 80 = 4000 minutes = 70h
With 7h work per day the result can be achieve in 10 work days.